|
Home | Forums | Gallery | Webcams | Blogs | YouTube Channel | Classifieds | Calendar | Register | FAQ | Donate | Members List | Today's Posts | Search |
|
Thread Tools | Display Modes |
08-14-2011, 09:42 PM | #1 |
Senior Member
Join Date: Jun 2005
Location: Exeter NH
Posts: 596
Thanks: 0
Thanked 1,027 Times in 224 Posts
|
Lat/Lon distance question
Can somebody tell me how far apart-in feet-two objects are given the following Lat/Lon specs.
Lat/Lon format I'm using is xx yy.zzz Object #1 48 36.579 / 77 23.319 Object #2 48 36.568 / 77 27.359 When I hike I use the UTM/Universal Transverse Mercator coordinate system in the GPS-one convenient increment: meters, so you can tell exactly how far something is. Not so here at least I don't have a mind for the whole Lat/Lon thing and it variations. Thanks. |
08-15-2011, 06:22 AM | #2 |
Deceased Member
Join Date: Jul 2006
Location: Gilford, NH
Posts: 2,311
Thanks: 1,070
Thanked 2,054 Times in 497 Posts
|
Maybe this?
I used the numbers from the post and the ruler function on Google Earth, I added the N and W to the numbers you posted.
Frame of reference, these co-ordinates are in Canada
__________________
"Before you criticize someone, walk a mile in his shoes. That way, if he gets angry he'll be a mile away and barefoot!" unknown |
The Following User Says Thank You to SteveA For This Useful Post: | ||
Rusty (08-15-2011) |
08-15-2011, 07:05 AM | #3 |
Senior Member
Join Date: Mar 2008
Location: Welch Island and West Alton
Posts: 3,218
Thanks: 1,173
Thanked 2,002 Times in 915 Posts
|
We also use UTM on the GPS when hiking, easy to locate on the topo map.
To solve your geometry problem convert your lat/long to UTM, many sites out there such as http://www.rcn.montana.edu/resources...ordinates.aspx and http://www.ngs.noaa.gov/cgi-bin/utm_getut.prl Assuming your data is in degrees; decimal minutes format I get (subject to keyboard errors) a distance of 4,964.9 meters (16,289 feet) at a bearing of 88.4 degrees. Last edited by Slickcraft; 08-15-2011 at 11:03 AM. Reason: add result |
08-15-2011, 11:36 AM | #4 |
Deceased Member
Join Date: Jul 2006
Location: Gilford, NH
Posts: 2,311
Thanks: 1,070
Thanked 2,054 Times in 497 Posts
|
I'd go with Slickcraft's math
The way I did it was just using the ruler tool on Google earth and came up with the 16,181 shown in the clip I added. Definitely not an exact number because I'm just dragging it from point to point. Not very exact.
I'd say his is likely right on the money.
__________________
"Before you criticize someone, walk a mile in his shoes. That way, if he gets angry he'll be a mile away and barefoot!" unknown |
The Following User Says Thank You to SteveA For This Useful Post: | ||
Rusty (08-15-2011) |
08-15-2011, 11:49 AM | #5 |
Senior Member
Join Date: Oct 2010
Posts: 2,028
Thanks: 603
Thanked 687 Times in 425 Posts
|
I like the way that you did it.....pretty clever!!
|
Sponsored Links |
|
08-15-2011, 05:02 PM | #6 |
Senior Member
Join Date: Sep 2010
Location: Nashua, NH
Posts: 66
Thanks: 27
Thanked 16 Times in 6 Posts
|
In case you need to know - this is called a "Great Circle Distance" - as you are finding a distance between two points on a sphere. (Actually, an ellipsoid, but I'm assuming you don't need to be that accurate.)
I calculated a distance of 4.950 km or 16,240 feet. Quick calculator is: http://www.movable-type.co.uk/scripts/latlong.html |
08-19-2011, 07:35 AM | #7 |
Senior Member
Join Date: Jul 2005
Location: Thornton's Ferry
Posts: 1,296
Thanks: 67
Thanked 166 Times in 126 Posts
|
If you trust the "meters" result, multiply X39 1/3, then divide by 12.
|
08-19-2011, 04:29 PM | #8 |
Senior Member
Join Date: Jun 2005
Location: Exeter NH
Posts: 596
Thanks: 0
Thanked 1,027 Times in 224 Posts
|
Distance question
Thank you all-very helpful.
|
08-19-2011, 05:11 PM | #9 |
Senior Member
Join Date: Jun 2008
Location: Portsmouth. RI
Posts: 2,231
Thanks: 400
Thanked 460 Times in 308 Posts
|
Nautical Charts have the degrees, minutes and seconds ticked off..both across the bottom of the chart..look for the tick marks...AND vertically along the sides of the chart.
I can't speak for Topo Charts. ONE Degree of Latitude..that's on the SIDE of the chart running vertically along the side ..represents 60 Nautical Miles..which is somewhat more than a LAND Mile. SO: One Minute of Latitude would be ONE Mile. There is a conversion for Nautical miles to Land miles. You can take a pair of "dividers" and measure off the Minutes from the Side of the chart and then "take off" the distance with the dividers http://en.wikipedia.org/wiki/Dividers#Divider_caliper.. and measure in any direction to measure distance for short distances..hundreds of miles..? This.....with todays technology..is unnecessary. One minute of Latitude = one nautical mile...absolute... I learned this from my Study and Practice of Celestial Navigation in the late Seventy's... NB PS: I have pondered (days) whether to respond to this thread because the topic is "Technical" and I probably would not be able to describe it in "Ley" terms. Nobody does Celestial Navigation anymore. Post Note: I could explain the Miles..Vs Nautical Miles..MPH...Vs Knots...it's all wrapped up in conversions.......but it would just get worse.......... Last edited by NoBozo; 08-19-2011 at 06:24 PM. |
08-19-2011, 06:49 PM | #10 |
Senior Member
Join Date: Mar 2008
Location: Welch Island and West Alton
Posts: 3,218
Thanks: 1,173
Thanked 2,002 Times in 915 Posts
|
IMHO the UTM system is the easiest to use.
http://en.wikipedia.org/wiki/Univers...rdinate_system It was developed by the Army and is still used by the artillery folk. The easterly is meters east of a reference line within one of sixty zones. The northerly is simply meters north of the equator. The grid on a USGS TOPO map is a square kilometer grid with the UTM coordinates noted at each grid line. I can't see why anyone would want to use a lat/long system in the field. |
Bookmarks |
|
|